Answer:(a) 0.35Hz (b) 0.37Hz (c) 0
Explanation: frequency of a simple pendulum is expressed as ;
f= 1/2π√(a/L)
(a) in a room that is stationary, a, is the acceleration due to gravity =9.8m/s²
f= 1/2π√(g/L)
f= 1/2π( 9.8/2)
f= 0.35Hz
(b) If the pendulum is in an elevator accelerating at a rate of 1.1m/s²
The total force will surely to both a and g
Therefore apparent acceleration = a+g= 1.1 +9.8=10.9 m/s²
f= 1/2π √( 10.9/2)
f= 0.37Hz
(c) For a free fall, apparent acceleration is 0
f= 1/2π √ (0/L)
f = 0
