For 0.3 s the ball stays in the air.
Explanation:
Given.
length (L) = 7 inch
converting to (cm) and (m) we have = 17.78 cm = 0.1778 m
Angle (θ) = 35°
Speed (S) = 14 m/s = 1400 cm/s
t = ?
solution
The first step in this analysis of solving the projectile motion is to resolve the velocity components into both horizontal and vertical components.
v(vertical velocity) = 14 m/s * sin(35°)
= 14 × 0.573576 = 8.0299
= 8.0299 m/s
v(horizontal velocity) = 14 m/s × cos (35°)
= 11.468 m/s
we need to know the duration of time (T) the ball is in the air.
the formula is given as,
t = (v(horizontal) - v(vertical)) / a
a = -9.8 m/s
t = (-11.468 + 8.0299) / -9.8
t= 0.3508 s = 0.3 s
The ball stays in the air for a duration of 0.3 s
