Please match the proof
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Answer:
Δ ABC [tex]\sim[/tex] Δ DEF
Step-by-step explanation:
Given:
[tex]\frac{AB}{DE} = \frac{AC}{DF}= \frac{BC}{EF}[/tex]
W need to Prove Δ ABC [tex]\sim[/tex] Δ DEF
Solution:
Statement: Reason
[tex]\frac{AB}{DE} = \frac{AC}{DF}= \frac{BC}{EF}[/tex] a) Given
"While Constructing both the triangle the lines were made parallel."
DE ║ AB c) Construction of Δ DEF on to Δ ABC
" When the Lines are parallel then their corresponding angles are equal in measure."
∠A ≅ ∠ EDF and ∠C ≅ ∠ EFD d) Corresponding Angles of parallel lines
Now By AA similarity theorem which states that;
"When 2 angles of one triangle are congruent to corresponding 2 angles of another triangle then 2 triangles are said to be similar."
Δ ABC [tex]\sim[/tex] Δ DEF b) By AA Similarity theorem.