An object moves at a constant rate along a circular path with radius 10 inches, and makes 3 revolutions in 2 seconds.
What is the linear velocity, in inches per second, of a point on the edge of the wheel?
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Respuesta :

Answer:

94.28 inches/second.

Step-by-step explanation:

The length of the circumference of the circular path with 10 inches radius is = [tex]2\pi r = 2 \times \frac{22}{7} \times 10 = 62.85[/tex] inches.

Now, the point on the edge of the wheel moves by 3 revolutions in 2 seconds.

So, in 2 seconds the point moves a linear distance of (3 × 62.85) = 188.57 inches.

Therefore, the linear velocity of the point in inches per second is [tex]\frac{188.57}{2} = 94.28[/tex]  inches per second.

(Answer)

Answer:

30(3.14) or 30(pi)

Step-by-step explanation:

Got it right on edge

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