Question

At a certain time in the afternoon a light pole casts a shadow that is 7 foot 1 inch long. At the same time, a woman of height 5-foot 3-inches casts a shadow that is 45 in long. How tall is the light pole? ​

Answer 1

Answer:

$\displaystyle \frac{119}{144}\:ft.\:[9\frac{11}{12}\:in.]$

Step-by-step explanation:

$\displaystyle \frac{45}{5\frac{1}{4}} = \frac{7\frac{1}{12}}{lp} → \frac{[5\frac{1}{4}][7\frac{1}{12}]}{45} = lp → \frac{37\frac{3}{16}}{45} = lp → \frac{119}{144}\:ft. = lp$

* As you can see, the answer is in feet, so if you are comfortable working with inches, multiply the result by 12:

$\displaystyle 1\:ft. = 12\:in. \\ \\ 9\frac{11}{12} = [12][\frac{119}{144}]; 9\frac{11}{12}\:in.$

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