Answer:
0.572 Hz
Explanation:
given,
length of simple pendulum, l = 0.76 m
mass of the bob, m = 365 g = 0.365 Kg
angle made from the vertical, = 12°
frequency, f = ?
[tex]f = \dfrac{1}{2\pi}\sqrt{\dfrac{g}{L}}[/tex]
[tex]f = \dfrac{1}{2\pi}\sqrt{\dfrac{9.8}{0.76}}[/tex]
[tex]f = \dfrac{1}{2\pi}\times 3.59[/tex]
f = 0.572 Hz
The frequency at which pendulum vibrates is equal to 0.572 Hz