Answer:
[tex] x=2, y=3, z=4+t[/tex]
Step-by-step explanation:
For this case we need a line parallel to the plane x z and yz. And by definition of parallel we see that the intersection between the xz and yz plane is the z axis. And we can take the following unitary vector to construct the parametric equations:
[tex] u= (u_x, u_y, u_z)= (0,0,1)[/tex]
Or any factor of u but for simplicity let's take the unitary vector.
Then the parametric equations are given by:
[tex] x= P_x + u_x t[/tex]
[tex] y= P_y + u_y t[/tex]
[tex] z= P_z + u_z t[/tex]
Where the point given [tex] P=(2,3,4)= (P_x , P_y, P_z) [/tex]
And then since we have everything we can replace like this:
[tex] x= P_x + u_x t 2+ 0*t = 2[/tex]
[tex] y= P_y + u_y t= 3+ 0*t = 3[/tex]
[tex] z= P_z + u_z t = 4+ 1t = 4+t[/tex]
[tex] x=2, y=3, z=4+t[/tex]