Answer:
[tex] P_2_{abs}=160\ psia[/tex] (absolute).
Explanation:
Given that
Pressure ratio r
r=8
[tex]r=\dfrac{P_2_{abs}}{P_1_{abs}}[/tex]
[tex]8=\dfrac{P_2_{abs}}{P_1_{abs}}[/tex] -----1
P₁(gauge) = 5.5 psig
We know that
Absolute pressure = Atmospheric pressure + Gauge pressure
Given that
Atmospheric pressure = 14.5 lbf/in²
P₁(abs) = 14.5 + 5.5 psia
P₁(abs) =20 psia
Now by putting the values in the above equation 1
[tex]8=\dfrac{P_2_{abs}}{20}[/tex]
[tex] P_2_{abs}=8\times 20\ psia[/tex]
[tex] P_2_{abs}=160\ psia[/tex]
Therefore the exit gas pressure will be 160 psia (absolute).