Question

Hiro has a stack of cards with one number from the set 1, 1, 2, 2, 3, 3, 3, 4 written on each card. What is the probability that he pulls out a 3 first and then pulls out a 2 without replacing them?

1/64
1/56
3/32
3/28

Answer 1

There are a total of 8 cards on the stack with two 1's, two 2's, three 3's and one four. For the first case, the probability of pulling 3 from the stack is 3/8. The situation is that there is no replacement such that on the second case, the number of cards on the stack is only 7. The probability of picking 2 out of the stack is 2/7. The overall probability is the product of the probabilities of the first and second case. Thus, the answer is 3/28. 

Answer 2

The probability that he pulls out a 3 first and then pulls out a 2 without replacing them is 3/28

What is probability?

Probability is the likelihood or chance that an event will occur

Given the number from the set 1, 1, 2, 2, 3, 3, 3, 4 written on each card, the total outcome will be 8

If 3 is pulled out first, the probability of pulling 3 out is given as 3/8

Probability of pulling 2 out without replacing 3 is 2/7

Pr(pulls out a 3 first and then pulls out a 2 without replacing them) = 3/8 * 2/7 = 3/28

Hence the probability that he pulls out a 3 first and then pulls out a 2 without replacing them is 3/28

Learn more on probability here: https://brainly.com/question/24756209

#SPJ5