Question

The area of a rectangle is 56 cm. The length is 2 cm more than x and the width is 5 cm less than
twice x. Solve for x. Round to the nearest whole number.

Answer 1

The value of x is 6 cm.

Step-by-step explanation:

Given,

Area of rectangle = 56 cm

Length of rectangle = x+2

Width of rectangle = 2x-5

Area = Length * Width

$56=(x+2)(2x-5)\\56=2x^2-x-10\\0=2x^2-x-10-56\\2x^2-x-66=0$

Factorizing

$2x^2+11x-12x-66=0\\x(2x+11)-6(2x+11)=0\\(2x+11)(x-6)=0$

Either,

2x+11 = 0          => 2x=-11

Or,

x-6=0               => x=6

As x is added to dimension, it cannot be negative.

Therefore,

The value of x is 6 cm.

Keywords: rectangle, factorization

Learn more about factorization at:

• brainly.com/question/11921476
• brainly.com/question/1232765

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