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Arnoldo needs to write this system in slope-intercept form. Which shows how he could do that?
3x-2y=6
0.4(2oy+15)=x

Respuesta :

Answer:

[tex]y = \frac{3}{2}x - 3[/tex]

[tex]y = \frac{1}{8} x - \frac{7}{8} [/tex]

Step-by-step explanation:

The given system is

3x-2y=6

0.4(20y+15)=x

The slope intercept form is y=mx+c.

For the first equation, 3x-2y=6, we add -3x to both side -2y=-3x+6

[tex]y = \frac{3}{2}x - 3[/tex]

For 0.4(20y+15)=x, we expand to get:

[tex]8y + 7 = x[/tex]

[tex]8y= x - 7[/tex]

Divide through by 8

[tex]y = \frac{1}{8}x - \frac{7}{8} [/tex]

Therefore the system in slope-intercept form is:

[tex]y = \frac{3}{2}x - 3[/tex]

[tex]y = \frac{1}{8}x - \frac{7}{8} [/tex]

Answer:

y=3/2x-3

y=1/8x-3/4

Step-by-step explanation:

I plugged these equations into an algebra calculator, the result was this. I also did the question on edge. TRUST ME LOL

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