Respuesta :
Answer:
c) A rectangle with width of 9 mm and length of 45 cm.
d) A rectangle with width of 10 cm and length of 44 cm.
Step-by-step explanation:
Given:
Length of the rectangle = 32 in.
Width of the rectangle = 8 in.
First we will find the ratio of length by width.
[tex]\frac{length}{width}= \frac{32}{8} = \frac{4}{1} \ \ \ \ equation \ 1[/tex]
Now we need to find from the given Option which rectangles are not similar to Carl's Rectangle.
So we will check for each.
a) A rectangle with width of 23 cm and length of 92 cm.
we will find the ratio of length by width.
[tex]\frac{length}{width}= \frac{92}{23} = \frac{4}{1} \ \ \ \ equation \ 2[/tex]
By Definition of Similar rectangles which states that;
"When ratio of the dimension of 2 corresponding rectangles are equal then the 2 rectangles are said to be similar."
Now Comparing equation 1 and equation 2 we get;
equation 1 [tex]=[/tex] equation 2
Hence This rectangle is similar to Carl's rectangle.
b) A rectangle with width of 2.5 inch and length of 10 inch.
we will find the ratio of length by width.
[tex]\frac{length}{width}= \frac{10}{2.5} = \frac{4}{1} \ \ \ \ equation \ 2[/tex]
By Definition of Similar rectangles which states that;
"When ratio of the dimension of 2 corresponding rectangles are equal then the 2 rectangles are said to be similar."
Now Comparing equation 1 and equation 2 we get;
equation 1 [tex]=[/tex] equation 2
Hence This rectangle is similar to Carl's rectangle.
c) A rectangle with width of 9 mm and length of 45 cm.
we will find the ratio of length by width.
[tex]\frac{length}{width}= \frac{45}{9} = \frac{5}{1} \ \ \ \ equation \ 2[/tex]
By Definition of Similar rectangles which states that;
"When ratio of the dimension of corresponding rectangles are equal then the 2 rectangles are said to be similar."
Now Comparing equation 1 and equation 2 we get;
equation 1 [tex]\neq[/tex] equation 2
Hence This rectangle is not similar to Carl's rectangle.
d) A rectangle with width of 10 cm and length of 44 cm.
we will find the ratio of length by width.
[tex]\frac{length}{width}= \frac{44}{10} = \frac{11}{5} \ \ \ \ equation \ 2[/tex]
By Definition of Similar rectangles which states that;
"When ratio of the dimension of corresponding rectangles are equal then the 2 rectangles are said to be similar."
Now Comparing equation 1 and equation 2 we get;
equation 1 [tex]\neq[/tex] equation 2
Hence This rectangle is not similar to Carl's rectangle.