Two identical cars, one on the moon and one on the earth, have the same speed and are rounding banked turns that have the same radius r. There are two forces acting on each car, its weight mg and the normal force FN exerted by the road. Recall that the weight of an object on the moon is about one-sixth of its weight on earth. How does the centripetal force on the moon compare with that on the earth? (a) The centripetal forces are the same. (b) The centripetal force on the moon is less than that on the earth. (c) The centripetal force on the moon is greater than that on the earth.

The answer to the question that "How does the centripetal force on the moon compare with that on the earth?" is "(a) The centripetal forces are the same."

The centripetal force on an object is given by the following simple formula:

[tex]F_c = \frac{mv^2}{r}[/tex]

where,

Fc = centripetal force

m = mass of the object

v = speed

r = radius of the circular path

Now, it is clear from the formula that the centripetal force primarily depends upon three factors, which are, mass of object, speed, and radius of the circular path.

In this scenario, the masses of cars must be the same anywhere in the universe. The speed of cars and the radii of the circular paths are also given to be the same. Hence, the centripetal force acting on both cars must also be the same.

Learn more about centripetal force here:

brainly.com/question/11324711?referrer=searchResults

The attached picture shows the centripetal force.