Answer:
[tex]v_f_{book}=3.66m/sec[/tex] towards front of the ship
Explanation:
Mass of the astronaut [tex]m_1=58.5kg[/tex]
Mass of the book [tex]m_2=2.5kg[/tex]
Initially common velocity of astronaut and book v = 0.15 m /sec
After throwing book astronaut will come to the rest
So final velocity of astronaut [tex]v_f_{astronaut}=0[/tex]
We have to find the final velocity of the book
According to conservation of momentum
[tex](m_1+m_2)v=m_1v_f_{astronaut}+m_2v_f_{book}[/tex]
[tex](58.5+2.5)\times 0.15=58.5\times0+2.5\times v_f_{book}[/tex]
[tex]v_f_{book}=3.66m/sec[/tex] towards front of the ship