Question

3. An object of mass m is moving with a speed of v0 to the right on a horizontal frictionless surface, when it explodes into two pieces. Subsequently, on piece of mass 3/5 m moves with a speed of v0/2 to the left. The speed and direction of the other piece of the object is ______________.

Answer 1

Answer:

The speed of the other piece of the object is 13/4*v0, going to the right.

Explanation:

Assuming that no external forces acting during the explosion (as the time during which it happens is considered infinitesimal), total momentum must be conserved , same as it happens with the total mass, assuming that v₀ is much smaller than c (speed of light), so no conversion of mass into energy is done.

So, based on the information provided, we can write the following expression, assuming the positive direction to be the one  to the right:

m*v₀ = -3/5*m*(v₀/2) + 2/5*m*vₓ

Solving for vₓ, we have:

vₓ = 13/4*v₀, to the right, as the value obtained is positive.

Answer 2

The speed & distance of the other piece of the object is 13/4*v0, going to the right.

Calculation of the speed and the direction:

Since on piece of mass 3/5 m moves with a speed of v0/2 to the left.

So,

m*v₀ = -3/5*m*(v₀/2) + 2/5*m*vₓ

Now we have to solve  for vₓ,

So,

vₓ = 13/4*v₀,

It should be to the right, since the value obtained is positive.

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