Hint: The y angle and the (3x - 26) angle are vertical angles. So are the (x+y) and 102 angles. Use those facts to write a two equation system and solve it for x and y. Then you'll be able to find angle IMN
![Hint The y angle and the 3x 26 angle are vertical angles So are the xy and 102 angles Use those facts to write a two equation system and solve it for x and y Th class=](https://us-static.z-dn.net/files/db4/208b19fcd394a4f03ca0e86afce24cec.png)
Answer:
[tex]\angle IMN = 70\°[/tex]
Step-by-step explanation:
Given:
[tex]\angle IMN = y\°\\\\\angle M =(3x-26)\°\\\\\angle JIL =102\°\\\\\angle KIM = (x+y)\°[/tex]
We need to find the ∠ IMN
Solution:
Now we know that;
∠ IMN = ∠ M ( Vertically opposite angles)
Substituting the values we get;
[tex]y =3x-26\\\\3x-y =26 \ \ \ \ equation \ 1[/tex]
Also We know that;
∠ JIL = ∠ KIM ( Vertically opposite angles)
Substituting the values we get;
[tex]x+y =102 \ \ \ \ equation \ 2[/tex]
Now adding equation 1 and equation 2 we get
[tex](3x-y)+(x+y) =102+26\\\\3x-y+x+y = 128\\\\4x=128[/tex]
Dividing both side by 4 using division property of equality we get;
[tex]\frac{4x}{4} = \frac{128}{4}\\ \\x= 32[/tex]
Now Substituting the value of 'x' in equation 2 we get;
[tex]x+y=102\\\\32+y =102\\\\y =102-32 = 70[/tex]
Hence [tex]\angle IMN = 70\°[/tex]