On average, an adult person breathes in about 10 liters of air per minute. Assuming atmospheric pressure and 20°C air temperature, estimate the mass of air in kilograms that a person breathes in per day. The mass of air in kilograms that a person breathes in per day is ___ kg.

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Answer:

The mass of air in kilograms that a person breathes in per day is found toe be 17.352 kg.

Explanation:

The volume intake in the whole day will be given by:

Volume = V = (10 liter/min)(60 min/ 1hr)(24 hr/ 1 day)

V = (14400 liter)(0.001 m^3/ 1 liter)

V = 14.4 m^3/day

Temperture = 20°C = 293 k

Pressure = 1 atm = 101325 N/m²

General gas constant = R = 8.314 J/mol. k

Thus, using general gas equation:

PV = nRT

since,   n = m/M

where, n = no. of moles of air

            m = mass in grams of air

            M = molecular mass of air = 28.97 g/mol

therefore,

PV = (m/M)RT

m = PVM/RT

m = (101325 N/m²)(14.4 m^3/day)(28.97 g/mol)/(8.314 J/mol.k)(293 k)

m = 17352 g/day

m = 17.352 kg/day

The mass of air in kilograms that a person breathes in per day is;

17.3376 kg.

We are given;

Volume of air per minute; v' = 10 L/min = 0.01 m³/min = 14.4 m³/day

Temperature; T = 20°C

Now, formula for density is;

ρ = m/v

where;

ρ is density

m is mass

v is volume

From tables online, the density of air at 20°C air temperature and atmospheric pressure is; ρ = 1.204 kg/m³

From the density equation, we now have;

1.204 = m'/14.4

where m' is the mass of air per day

Thus;

m' = 1.204 × 14.4

m' = 17.3376 kg per day

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