Respuesta :
Answer: Option (b) is the correct answer.
Explanation:
The given data is as follows.
[tex]K.E_{1}[/tex] = 30 J, l = 10 cm = 0.1 m (as 1 m = 100 cm)
F = 10 N
The formula to calculate the work done is as follows.
W = [tex]F \times l[/tex]
Hence, putting the given values into the above formula as follows.
W = [tex]F \times l[/tex]
= [tex]10 N \times 0.1 m[/tex]
= 1 J
As the dart loses 1 joule of energy when it goes through the barrel. Therefore, the kinetic energy it has when it comes out is calculated as follows.
K.E = 30 - 1
= 29 J
Thus, we can conclude that the kinetic energy of the fired dart is 29 J.
Answer: Option (b) is the correct answer.
Explanation:
The given data is as follows.
= 30 J, l = 10 cm = 0.1 m (as 1 m = 100 cm)
F = 10 N
The formula to calculate the work done is as follows.
W =
Hence, putting the given values into the above formula as follows.
W =
=
= 1 J
As the dart loses 1 joule of energy when it goes through the barrel. Therefore, the kinetic energy it has when it comes out is calculated as follows.
K.E = 30 - 1
= 29 J
Thus, we can conclude that the kinetic energy of the fired dart is 29 J.