given
h(t)=-16t^2+25t+3
assume h(t) is height measured upwards from ground.
Need h(t)=0 for t>0.
solve
h(t)=-16t^2+25t+3=0
use quadratic formula, A=-16, B=25, C=3
t=(-B +/- sqrt(B^2-4AC))/2A
=-25-sqrt(25^2+192)/(-32)
= {-0.11198, 1.6745} seconds
reject negative root, so
time = 1.6745 seconds.