Answer:
Explanation:
The method we have to use is linear depreciation.
We will first find the slope:
[tex]Slope=\frac{V_{2}-V_{1}}{Y_{2}-Y_{1}}[/tex]
where:
V_2 is the machine value after 5 years.
V_1 is the machine value after 2 years.
Y_1 = 2 years
Y_2 = 5 years
[tex]Slope=\frac{130000-670000}{5-2}[/tex]
[tex]Slope=-180,000[/tex]
Now:
[tex]Slope=\frac{V_{2}-V}{Y_{2}-Y}[/tex]
where:
V is the machine value at t ≥ 0.
Y is the years at t ≥ 0.
[tex]-180,000=\frac{130000-V}{5-Y}[/tex]
Rearranging the above expression.
[tex]V=130000+180000(5-Y)[/tex]
Formula for the machine value = [tex]V=130000+180000(5-Y)[/tex]