Question

Fayola has 6 more than 3 times the number of cans Aaron has.George has 4 more than twice the number of cans fayola has. A. Write an expression for the number of cans Fayola has. B. Write an expression for the number of cans George has. C. Aaron has seven cans how many do Fayola and George have

Answer 1

Answer:

A. An expression for the number of cans Fayola has is $y=3x+6$.

B. An expression for the number of cans George has is $z= 6x+16$.

C. Fayola will have 27 cans and George will have 58 cans.

Step-by-step explanation:

Let the number of can's Aaron has be 'x'.

Let the number of can's Fayola has be 'y'.

Let the number of can's George has be 'z'.

Given:

Fayola has 6 more than 3 times the number of cans Aaron has.

It means that Number of cans Fayola has is equal to 3 times number of cans Aaron has plus 6.

framing in equation form we get;

$y=3x+6 \ \ \ \ equation \ 1$

A. Hence An expression for the number of cans Fayola has is $y=3x+6$.

Also Given:

George has 4 more than twice the number of cans fayola has.

It means that Number of cans George has is equal to 2 times number of cans Fayola has plus 4.

framing in equation form we get;

$z=2y+4$

But $y=3x+6$, we will substitute the same we get;

$z=2(3x+6)+4 \\\\z= 6x+12+4\\\\ z= 6x+16 \ \ \ \ equation\ 2$

B. Hence An expression for the number of cans George has is $z= 6x+16$.

Now Given:

Aaron has 7 cans.

Hence x =7, we will substitute in equation 1 and equation to find the value of 'y' and 'z'

$y =3x+6\\\\y =3\times 7 +6\\\\y =21+6 =27\ cans$

Also;

$z=6x+16\\\\z= 6\times 7 +16\\\\z =42+16 = 58\ cans$

C. Hence Fayola will have 27 cans and George will have 58 cans.