Question

a volume of helium occupies 11.0 L at a pressure of 98.0 kpa. what is the new volume if the pressure drops to 86.2 kpa​

Answer 1

12.506 L

Explanation:

We’ll use Boyle's Law of ideal gases;

P₁V₁ = P₂V₂      whereby;

P – pressure

V – volume

We replace variable with given values;

98 * 11 = 86.2 * V₂

V₂ = 98 * 11 / 86.2

V₂ = 12.506 L

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