Question

A 12.2-m-radius Ferris wheel rotates once each 28 s. (a) What is its angular speed (in radians per second)?(b) What is the linear speed of a passenger?___________m/s(c) What is the acceleration of a passenger?_____________m/s2

Answer 1

Answer:  

(a) 0.2165 rad/sec

(b) 2.6143 m /sec

(C) $0.459rad/sec^2$

Explanation:

It is given that wheel rotates each revolution in 29 sec

So time period T = 29 sec

(a) Angular speed is equal; to $\omega =\frac{2\pi }{T}=\frac{2\times 3.14}{29}=0.2165rad/sec$

(b) Radius is given r = 12.2 m

So linear velocity $v=\omega r=0.2165\times 12.2=2.6143m/sec$

(C) Angular acceleration is given by $a=\frac{v^2}{r}=\frac{2.6143^2}{12.2}=0.459rad/sec^2$