Question

The first stage of a Saturn V space vehicle consumes fuel at the rate of 8140 kg/s, with an exhaust speed of 1950 m/s. The acceleration of gravity is 9.8 m/s 2 . Calculate the thrust produced by these engines. Answer in units of N.

Answer 1

The thrust of a rocket can be defined as the product between the speed and the rate of spent fuel. Mathematically this expression is given as,

$T = u \frac{dM}{dt}$

Here,

$\frac{dM}{dt}$ = Rate fuel

u = Velocity

Our values are given as,

$\frac{dM}{dt} = 8140kg/s$

Exhaust speed of the gas coming out from the rocket is

$u = 1950m/s$

The thrust produced by the engine is given by

$T = u \frac{dM}{dt}$

$T = (8140)(1950)$

$T = 1.5873*10^7N$

Answer 2

A force required for the motion of the rocket through the air and space is called thrust. The thrust produced by the vehicle engine is $1.58\times 10^7\;\rm N$.

How do you calculate the thrust of the engines?

The Saturn V consumes the fuel at a rate of 8140 kg/s and its exhaust speed is 1950 m/s. Gravitational acceleration is 9.8 m/s.

The thrust of the engine can be calculated as given below.

Thrust = $m\times v$

Where m is the mass of fuel consumed by the engine and v is the velocity at the time of exhaust.

Thrust = $8140 \times 1950$

Thrust = $1.58 \times 10^7\;\rm N$

Hence we can conclude that the thrust produced by the vehicle engine is $1.58\times 10^7\;\rm N$.

To know more about the thrust of the engine, follow the link given below.

https://brainly.com/question/14383089.