A 0.200 kg plastic ball moves with a velocity of 0.30 m/s. It collides with a second plastic ball of mass 0.100 kg, which is moving along the same line at a speed of 0.10 m/s. After the collision, both balls continue moving in the same, original direction, and the speed of the 0.100 kg ball is 0.26 m/s. What is the new velocity of the first ball?

The total momentum of the System is conserved. Total momentum of the system before the collision is equal to the total momentum of the system after collision. The total momentum is the sum of individual momentum of all the objects in that system.

momentum of an object = mass* velocity

Total Momentum before collision = 0.2*0.3 + 0.1*0.1= 0.07 kg⋅m/s;

Total momentum after collision = 0.1*0.26 + 0.2*x = 0.07;

Solve for x.

asuwafohjames asuwafohjames · Answer 2 · 2021-12-07T11:47:17+01:00

The new velocity of the first ball after collision is 0.22 m/s

Applying the law of conservation of momentum.

Law of conservation of momentum: In a closed system, the total momentum of the system before collision is equal to the total momentum of the system after collision.

From the question,

Since both plastic balls move with different velocity after collision,

Then the collision is an elastic collision.

Applying,

mu+MU = mv+MV................ Equation 1

Where m = mass of the first plastic ball, u = initial velocity of the first plastic ball, M = mass of the second plastic ball, U = initial velocity of the seconds plastic ball, v = final velocity of the first plastic ball, V = Final velocity of the second plastic ball.

From the question,

Given: m = 0.20 kg, u = 0.30 m/s, M = 0.10 kg, U = 0.10 m/s, V = 0.26 m/s.

Substitute these values into equation 1

0.2(0.3)+0.1(0.1) = 0.1(0.26)+0.2(v)

0.06+0.01 = 0.026+0.2v

0.07-0.026 = 0.2v

0.2v = 0.044

v = 0.22 m/s

Hence, the new velocity of the first ball is 0.22 m/s

Learn more about conservation of momentum here: https://brainly.com/question/22257327