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How long is a pendulum with a period of 1.0 s on a planet with twice the gravity of the earth?


0.25 m


1.0 m


0.50 m


0.10 m

Respuesta :

Explanation:

T = 2π √(L / g)

1.0 s = 2π √(L / 19.6 m/s²)

L = 0.50 m

Answer:

0.50 m

Explanation: