Answer:
[tex]\large \boxed{\text{A. 0.930 mol Na; B. 0.465 mol of H}_{2}}[/tex]
Explanation:
A. Moles of Na
1 mol Na atoms = 5.60 × 10²³ atoms of Na
[tex]\text{Moles of Na } = 5.60 \times 10^{23} \text{ atoms Na} \times \dfrac{\text{1 mol Na}}{6.022 \times 10^{23}\text{ atoms Na}}\\\\= \text{0.930 mol Na}\\\text{There are $\large \boxed{\textbf{0.930 mol Na}}$ in 5.60 $\times 10^{23}$ atoms of Na.}[/tex]
B. Moles of hydrogen
You haven't given the equation for the reaction. However, we can write an equation
2Na + 2HX ⟶ 2NaX+ H₂
n/mol: 0.930
1 mol of H₂ is formed from 2 mol of Na
[tex]\text{Moles of H}_{2} = \text{0.930 mol Na} \times \dfrac{\text{1 mol H}_{2}}{\text{2 mol Na}} = \textbf{0.465 mol H}_{2}\\\\\text{You can form $\large\boxed{\textbf{0.465 mol of H}_{2}}$}[/tex]
