Question

12.) Write y = 1/6 x + 7 in standard form using integers.

a.) –x + 6y = 42

b.) –x + 6y = 7

c.) 6x – y = 42

d.) –x – 6y = 42

Answer 1

Option A

-x + 6y = 42 is the standard form

Solution:

Given that we have to write $y = \frac{1}{6}x+7$ in standard form

The standard form of an equation is Ax + By = C

In this kind of equation, x and y are variables and A, B, and C are integers

Given equation is:

$y = \frac{1}{6}x+7$

Let us convert the above equation into standard form

$y = \frac{x}{6} + 7$

$y = \frac{x}{6} + \frac{7}{1}$

Make the denominator same in R.H.S

$y = \frac{x}{6} + \frac{7 \times 6}{1 \times 7}$

Solve the above equation

$y = \frac{x}{6} + \frac{42}{6}$

$y = \frac{x+42}{6}$

Move 6 from R.H.S to L.H.S

$6y = x + 42$

Bring all the terms to one side, leaving only constant on R.H.S

$-x + 6y = 42$

The above equation is of form Ax + By = C

Thus option A is correct