Question

In 1990 Walter Arfeuille of Belgium lifted a 281.5 kg object through a distance of 17.1 cm using only his teeth.a. How much work did Arfeuille do on the object?b. What magnitude force did he exert on the object during the lift, assuming the force was constant?

Answer 1

Answer:

(a) Work done is 471.74 J

(b) 2.758 kN

Solution:

As per the question:

Mass of the Walter Arfeuille, m = 281.5 kg

Distance, d = 17.1 cm = 0.171 m

Now,

(a) To calculate the work done:

Weight of Walter Afrueille, w = mg = $281.5\times 9.8 = 2758.7\ N$

Work done is given by:

W = mgd = wd

$W = 2758.7\times 0.171 = 471.74\ J$

(b) To calculate the magnitude of force exerted by Walter Arfeuille on the object is equal to the his weight:

F = w = mg = $281.5\times 9.8 = 2758.7\ N$

F = 2.758 kN