Answer:
The mole fraction of methanol in this mixture is 0.745
Explanation:
Molecular weight of methanol in the mixture = 32.04g/mol
Molecular weight of ethanol in the mixture = 46.07g/mol
Average molecular weight of mixture = 43.01g/mol
Mole fraction of methanol = molecular weight of methanol ÷ average molecular weight of mixture = 32.04g/mol ÷ 43.01g/mol = 0.745
Answer:
The mol fraction of methanol is 0.2181
Explanation:
Step 1: Data given
Molar mass of methanol = 32.04 g/mol
Molar mass of ethanol = 46.07 g/mol
Average molecular weight = 43.01 g/mol
Step 2: Calculate the mol fraction of methanol
Mol fraction = number of moles / total number of moles
We know that mol fraction of methanol + mol fraction of ethanol = 1
Mol fraction methanol = 1 - mol fraction of ethanol
X = 1-Y
Let's consider methanol = X and ethanol = Y
32.04*X + 46.07*Y = 43.01
32.04*(1-Y) +46.07Y = 43.01
32.04 - 32.04Y + 46.07Y = 43.01
14.03 Y = 10.97
Y = 0.7819
The mol fraction of ethanol is 0.7819
The mol fraction of methanol is 1 - 0.7819 = 0.2181
