Respuesta :

Answer:

H⁺(aq)

Explanation:

Let's consider the following redox reaction.

Sn(s) + 2 H⁺(aq) → Sn²⁺(aq) + H₂(g)

We can identify both half-reactions.

Oxidation: Sn(s) → Sn²⁺(aq) + 2 e⁻

Reduction: 2 H⁺(aq) + 2 e⁻ → H₂(g)

Sn(s) undergoes oxidation so it is the reducing agent, while H⁺(aq) undergoes reduction so it is the oxidizing agent.

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