Question

The ratio of the distance a 7-iron and a 5-iron will drive a golf ball 5to6. If a golfer averages 181 yards with a 7-iron, how far should he average with a 5-iron?

Answer 1

He should average 217.2 yards with 5 - iron

Solution:

Given that,

Ratio of the distance a 7-iron and a 5-iron will drive a golf ball 5 to 6

$\frac{\text { Distance using } 7 \text { iron }}{\text { Distance using } 5 \text { iron }}=\frac{5}{6}$

The golfer averages 181 yards with a 7-iron

Let "x" be the average with 5 - iron

Therefore,

$\frac{181}{x}=\frac{5}{6}$

Cross mulitply to get value of "x"

$6 \times 181=5 \times x\\\\5x = 1086\\\\x = \frac{1086}{5}\\\\x = 217.2$

Thus he should average 217.2 yards with 5 - iron