Question

Which would prove that ΔABC ~ ΔXYZ? Select two options.

StartFraction B A Over Y X = StartFraction B C Over Y Z EndFraction = StartFraction A C Over X Z EndFraction
StartFraction B A Over Y X = StartFraction B C Over Y Z EndFraction , angle C is-congruent-to angle Z
StartFraction A C Over X Z EndFraction = StartFraction B A Over Y X EndFraction , Angle A is-congruent-to Angle X
StartFraction B A Over Y X EndFraction = StartFraction A C Over Y Z EndFraction = StartFraction B C Over X Z EndFraction
StartFraction B C Over X Y EndFraction = StartFraction B A Over Z X EndFraction , Angle C is-congruent-to angle X.

Answer 1

Answer:

• StartFraction B A Over Y X = StartFraction B C Over Y Z EndFraction = StartFraction A C Over X Z EndFraction
• StartFraction A C Over X Z EndFraction = StartFraction B A Over Y X EndFraction , Angle A is-congruent-to Angle X

Step-by-step explanation:

For similarity of triangles, it is sufficient to show corresponding sides are proportional (first choice). (SSS)

It is also sufficient to show two corresponding sides are proportional and the angle between them is congruent (third choice). (SAS)

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IMO, it would be much easier to read the answer choices if they were written using appropriate symbols:

  BA/YX = BC/YZ = AC/XZ

  AC/XZ = BA/YX, ∠A≅∠X

Answer 2

Answer:

options a,c

Step-by-step explanation:

because i said