Answer:
20 seconds
Explanation:
t = Time taken
u = Initial velocity
v = Final velocity
s = Displacement
r = Radius of robot = 0.5 m
[tex]\alpha[/tex] = Angular acceleration = 2 rad/s²
Linear acceleration is given by
[tex]a=r\alpha\\\Rightarrow a=0.5\times 2\\\Rightarrow a=1\ m/s^2[/tex]
[tex]s=ut+\frac{1}{2}at^2\\\Rightarrow 50=0t+\frac{1}{2}\times 1\times t^2\\\Rightarrow t=\sqrt{\frac{50\times 2}{1}}\\\Rightarrow t=10\ s[/tex]
While speeding up time taken is 10 seconds
[tex]v=u+at\\\Rightarrow v=0+1\times 10\\\Rightarrow v=10\ m/s[/tex]
[tex]s=ut+\frac{1}{2}at^2\\\Rightarrow 50=10t-\frac{1}{2}\times 1\times t^2\\\Rightarrow t=\sqrt{\frac{50\times 2}{1}}\\\Rightarrow 50=10t-0.5t^2\\\Rightarrow -5t^2+100t-500=0[/tex]
[tex]t=\dfrac{-100\pm \sqrt{100^2-4\left(-5\right)\left(-500\right)}}{2\left(-5\right)}\\\Rightarrow t=10\ s[/tex]
The time taken to slow down is 10 seconds
Total time the trial is rum is 10+10 = 20 seconds