Question

Determine the absolute pressure on the bottom of a swimming pool 30.0 m by 8.7 m whose uniform depth is 1.8 m .

Answer 1

Answer:

The absolute pressure at the bottom is 118983 pascals

Explanation:

The absolute pressure of on a fluid is:

$P_{abs}=P_{gauge}+P_{atm}$ (1)

with Patm the atmospheric pressure and Pgauge the pressure due the depth on the fluid that is :

$P_{gauge}=\rho gh$ (2)

With g the gravity acceleration, ρ the fluid density and h the depth, using (2) on (1):

$P_{abs}=\rho gh+P_{atm}$

A fast searching on physics books or websites you can find that g=9.81$\frac{m}{s^{2}}$, ρ=1000$\frac{kg}{m^{3}}$ for water and Patm=101325Pa , so:

$P_{abs}=(1000)(9.81)(1.8)+(101325)$

$P_{abs}=118983Pa$