Five sales men could sell 18 cars
Solution:
The number of cars sold is proportional to the number of salesmen
[tex]\text{Number of cars sold } \propto \text{Number of salesmen }[/tex]
Let "c" be the number of cars sold
Let "s" be the number of salesmen
Then we get,
[tex]c \propto s[/tex]
c = ks -------- eqn 1
Where "k" is the constant of proportionality
Three salesmen sold eleven cars
Therefore, substitute s = 3 and c = 11 in eqn 1
[tex]11 = k \times 3\\\\k = \frac{11}{3} = 3.67[/tex]
How many could five salesmen have sold ?
Therefore, s = 5 and c = ?
Substitute s = 5 and k = 3.67 in eqn 1
[tex]c = 3.67 \times 5\\\\c = 18.35 \approx 18[/tex]
Thus five men sold 18 cars