if the number of cars sold is proportional to the number of salesmen,and three salesmen sold eleven cars,how many could five salesmen have sold? round to the nearest whole number

Respuesta :

Five sales men could sell 18 cars

Solution:

The number of cars sold is proportional to the number of salesmen

[tex]\text{Number of cars sold } \propto \text{Number of salesmen }[/tex]

Let "c" be the number of cars sold

Let "s" be the number of salesmen

Then we get,

[tex]c \propto s[/tex]

c = ks -------- eqn 1

Where "k" is the constant of proportionality

Three salesmen sold eleven cars

Therefore, substitute s = 3 and c = 11 in eqn 1

[tex]11 = k \times 3\\\\k = \frac{11}{3} = 3.67[/tex]

How many could five salesmen have sold ?

Therefore, s = 5 and c = ?

Substitute s = 5 and k = 3.67 in eqn 1

[tex]c = 3.67 \times 5\\\\c = 18.35 \approx 18[/tex]

Thus five men sold 18 cars