Answer:
v' = 5.35 m/s
Explanation:
given,
mass of toy car 1, m = 11 g
speed of car 1 in right direction, u = 25 cm/s
mass of toy car 2,M = 23 g
speed of car 2 in left direction, u' = 31 cm/s
after collision
Speed of car 1 in left direction,v= 51 cm/s
speed of car 2,v' = ?
using conservation of momentum
m u + M u' = m v + M v'
taking motion in right direction as positive
11 x 25 + 23 x (-31) = 11 x (-51) + 23 v'
23 v' - 561 = -438
23 v' = 123
v' = 5.35 m/s
Speed of second car is 5.35 m/s in right direction.