does anyone know how to solve this? i dont remember doing any problems in class related to this and this single question alone has been stressing me out
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Answer:
The answer to your question is below
Step-by-step explanation:
Process
1.- Get two points of each line to find the equation of each line
Continuous line A (-10, 0) B (0, 9)
Dotted line C (-2, -3) D (0, -10)
Slope continuous line m = [tex]\frac{9 - 0}{0 + 10} = = \frac{9}{10}[/tex]
Slope dotted line m = [tex]\frac{-10 + 3}{0 + 2} = \frac{-7}{2}[/tex]
2.- Get the equation of each line
Continuous line y + 0 = 9/10 (x + 10)
y = 9/10x + 9
Dotted line y + 3 = -7/2(x + 2)
y + 3 = -7/2x - 7
y = -7/2x -7 - 3
y = -7/2x - 10
3.- Find the inequalities
Continuous line (we need the upper area of the line, we use ≥)
y ≥ 9/10x + 9
The Dotted line (we also need the upper area, we use >)
y > -7/2x - 10
Answer:
Step-by-step explanation:
If you have graphed linear equations and inequalities, working this should not be stressful. You are working backward from the graph to determine what the equation must be.
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For the solid line, the y-intercept is +9 (where it crosses the y-axis) and the slope is 1 unit of rise for each 1 unit of run. The slope-intercept form of the equation is then ...
y = x + 9
Since the line is solid and the shading is above it, the associated inequality is ...
y ≥ x + 9
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For the dashed line, the y-intercept is -10. The line has a "rise" of -4 for each 1 unit of run, so its slope is -4. The slope-intercept form of the equation is then ...
y = -4x -10
Since the line is dashed (does not include the "or equal to" case), and shading is above it, the associated inequality is ...
y > -4x -10
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In summary, the system of inequalities is ...
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If shading is below, then the relation symbol is < or ≤.
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You know that slope-intercept form of the equation of a line is ...
y = mx + b . . . . . . where m is the slope and b is the y-intercept