Jennifer have 8 quarters, 12 dimes and 36 nickels.
Step-by-step explanation:
Given,
Worth of coins = $5.00 = 5*100 = 500 cents
One quarter = 25 cents
One dime = 10 cents
One nickel = 5 cents
Let,
x = number of quarters
y = number of dimes
z = number of nickels
According to given statement;
25x+10y+5z=500 Eqn 1
y = x+4 Eqn 2
z = 3y
z = 3(x+4) => z = 3x+12 Eqn 3
Putting value of y and z from Eqn 2 and 3 in Eqn 1
[tex]25x+10(x+4)+5(3x+12)=500\\25x+10x+40+15x+60=500\\50x+100=500\\50x=500-100\\50x=400[/tex]
Dividing both sides by 50
[tex]\frac{50x}{50}=\frac{400}{50}\\x=8[/tex]
Putting x = 8 in Eqn 2
[tex]y=8+4\\y=12[/tex]
Putting x=8 in Eqn 3
[tex]z=3(8)+12\\z=24+12\\z=36[/tex]
Jennifer have 8 quarters, 12 dimes and 36 nickels.
Keywords: linear equation, substitution method
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