Question

Factored form of the given equation
6x2+2x-8=

Answer 1

Answer:

($x-1$) and ($x+\frac{4}{3})$ are the factors of the given equation

It can be written as $6x^2+2x-8=(x-1)(x+\frac{4}{3})$

Step-by-step explanation:

Given quadratic equation is $6x^2+2x-8=0$

To find the factored form of the given equation :

$6x^2+2x-8=0$

By using the formula for quadratic equation $ax^2+bx+c=0$ then the solution is $x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$ where a and b are coefficients of $x^2$ and x respectively

$x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

Substitute a=6, b=2 and c=-8 in the above equation we get

$x=\frac{-2\pm \sqrt{2^2-4(6)(-8)}}{2(6)}$

$=\frac{-2\pm \sqrt{4+192}}{12}$

$=\frac{-2\pm \sqrt{196}}{12}$

$=\frac{-2\pm 14}{12}$

$x=\frac{-2\pm 14}{12}$

Therefore $x=\frac{-2+14}{12}$ and $x=\frac{-2-14}{12}$

$x=\frac{12}{12}$ and $x=\frac{-16}{12}$

$x=1$ and $x=\frac{-4}{3}$

Therefore ($x-1$) and $(x+\frac{4}{3})$ are the factors of the given equation

It can be written as $6x^2+2x-8=(x-1)(x+\frac{4}{3})$