Answer:
The correct option is b.
Step-by-step explanation:
The given expression is
[tex]\frac{7!}{3!}[/tex]
The n! is defined as
[tex]n!=n\times (n-1)\times (n-2)\times ...\times 3\times 2\times 1[/tex]
[tex]\frac{7!}{3!}=\frac{7\times 6\times 5\times 4\times 3!}{3!}[/tex]
Cancel out the common factor 3! from numerator and denominator.
[tex]\frac{7!}{3!}=7\times 6\times 5\times 4[/tex]
[tex]\frac{7!}{3!}=840[/tex]
Therefore option b is correct.