Respuesta :
The correct answer among the options given is the first one. The cathode reaction for a nickel-cadmium dry cell is Cd + 2OH Cd(OH)2 + 2e. It should be remembered that at the cathode reduction always happen and reduction is the gain of electrons. As we can see from the half reaction, there is a gain of 2 electrons.
Answer:
The cathode reaction is NiO2 + H2O +2e- -> Ni (OH)2 + OH-
Explanation: