Question

Write the equation of the line that passes through (1 5) and (-2 14) in slope intercept form

A.y=3x+2
B. y=3x+8
C.y= -3x-2
D.y=-3x + 8

Answer 1

To deliver what is being asked of the given above, solve first for the slope of the line. Given two points the slope is calculated by,
 
                                    m = (y2 - y1) / (x2 -x1)
          
                                    m = (14 - 5) / (-2 - 1) = -3

Use the point - slope to write the equation of the line,
                    
                                        y - y2 = m(x - x2)
 
                                      y - 14 = -3(x - -2) 
                                        
                                         y = -3x + 8

Therefore, the answer is letter D. 

Answer 2

Here is your answer:

Solving the equation:

  $m = (y^2 - y^1) \div (x^2 -x^1)

m = (14 - 5) \div (-2 - 1) = -3

y - y^2 = m(x - x2)

y - 14 = -3(x - -2)

y = -3x + 8$

Therefore the answer is option D "y = -3x + 8."

Hope this helps!