Question

How many moles of NH3 are necessary to produce 0.824 mol N2

Answer 1

Answer:

1.648 moles of ammonia will be required to produce 0.824 moles of nitrogen gas.

Explanation:

$2NH_3\rightarrow N_2+3H_2$

According to reaction 1 mole of nitrogen gas is produced by 2 moles of ammonia.

Then, 0.824 moles of nitrogen gas will be produced by:

$\frac{2}{1}\times 0.824 mol=1.648 mol$

1.648 moles of ammonia will be required to produce 0.824 moles of nitrogen gas.

Answer 2

0.824 moles of nitrogen gas will be produced by 0.412 mol $\bold {NH_3}$ since the molar ratio of ammonia and nitrogen gas is 2:1.

What is the Mole concept?

A mole is the measurement of a certain number of molecules, atoms, or ions.

1 mole =  $6.02 \times 10^2^3$

Two moles $\bold {NH_3}$  are dissociated to produce 1 mole of $\bold N_2 {}$ and 3 moles of $\bold {H_2}$.

$\bold {2NH_3 \rightarrow N_2 +3H_2}$

Therefore, 0.824 moles of nitrogen gas will be produced by 0.412 mol $\bold {NH_3}$, since the molar ratio of ammonia and nitrogen gas is 2:1.

Learn more about Mole concept:

https://brainly.com/question/2094702