Question

How many solutions are there to the following system equations?
Use the linear combination method.
2d+e=8
d-e=4
A. The solution is (4,0)
B. There is no solution
C. There are an infinite number of solutions
D. The solution is (5,-2)

Answer 1

indinite

2d+e=8            d-e=4

common multiple=16, 32, 64

16-12=4    16-4=12