Question

The length of a new rectangular playing field is 4 yards longer than triple the width. if the perimeter of the rectangular playing field is 408 yards, what are it's dimensions?

Answer 1

the length is 4 yards longer than 3width so L = 3W+4
perimeter equal 408 yards

perimeter equal 2L +2W = 2(3W+4)+2W 

408 = 6W +8 +2W
400=8W

W = 50

L = 3*50 +4 = 154

L = 154
W = 50

P = 2L +2W
408 = 2*50 +2*154
408 = 100 +308
408 = 408

hope that this is easy understandably 

Answer 2

The dimensions of the new rectangular playing field are 50 yards and 154 yards respectively.

Let the width of the rectangle be represented by w

Let the length of the rectangle be = 3w + 4

Therefore, the perimeter will be:

2(w) + 2(3w + 4) = 408

2w + 6w + 8 = 408

8w + 8 = 408

Collect like terms

8w = 408 - 8

8w = 400

Divide both side by 8

8w/8 = 400/8

w = 50

Length = 3w + 4

= 3(50) + 4

= 150 + 4

= 154 yards

The dimensions of the new rectangular playing field are 50 yards and 154 yards respectively.

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