which answer shows the foil mthod used to expand the product below (2x+3)(2x^2-5)
a.2x*2x^2+2x*(-5)+3*2x+3*(-5)
b.2x*2x^2+2x*(-5)+3*2x^2+3*(-5)
c.2x*2x^2+3*2x^2+2x^2*(-5)+3*(-5)

Respuesta :

FOIL = First, Outside, Inside, Last

First - 2x*2x^2
Outside - 2x*(-5)
Inside - 3*2x^2
Last - 3*(-5)

Putting all of this together, we get 2x*2x^2 + 2x*(-5) + 3*2x^2 + 3*(-5), which would be option B
I think its 4x^3-10x+6x^2-15
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