Respuesta :
Let straight wings = AA
Let curly wings = aa
P: straight-winged x curly-winged
P: AA x aa
Should we use Punnett Square technique, all dominate alleles from straight-wingled parent will pair up with all recessive alleles from curly-winged parents; therefore,
F1 genotype: All Aa
F1 phenotype: All straight-winged
Let curly wings = aa
P: straight-winged x curly-winged
P: AA x aa
Should we use Punnett Square technique, all dominate alleles from straight-wingled parent will pair up with all recessive alleles from curly-winged parents; therefore,
F1 genotype: All Aa
F1 phenotype: All straight-winged
Answer:
Explanation:
Should we use Punnett Square technique, all dominate alleles from straight-wingled parent will pair up with all recessive alleles from curly-winged parents; therefore,
F1 genotype: All Aa
F1 phenotype: All straight-winged