The rectangle ABCD is centered at the origin. C has the coordinates (w, –v). Determine the length of a diagonal of ABCD.
A.[tex]2 \sqrt{w^2+v^2}[/tex]
B.[tex] 4\sqrt{w^2+v^2} [/tex]
C.2w+2v
D.2w+4v

Respuesta :

Sides of the rectangle ABCD are: 2 w and 2 v.
The length of a diagonal: [tex] \sqrt{(2w)^{2}+(2v)^{2} } = \sqrt{4w^{2} +4v ^{2} } = \\ \sqrt{4(w^{2} +v^{2} )}=2 \sqrt{w^{2} +v^{2} } [/tex]
Answer: A)

Answer: A.  is the answer to the question

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