Question

The solution set for 6a2 − a − 5 = 0 is?

Answer 1

a = 1, -5/6

you solve the equation for a, by finding a,b,c of the quadratic then applying the quadratic formula

Answer 2

The solution of the given quadratic equation 6a² − a − 5 = 0 will be a ( 1 , -5 / 6 ).

What is a quadratic equation?

The polynomial having a degree of two or the maximum power of the variable in a polynomial will be 2 is defined as the quadratic equation and it will cut two intercepts on the graph at the x-axis.

The solution of the given equation is as follows:-

6a² − a − 5 = 0

Using the factorization formula:-

$a = \dfrac{-b\pm\sqrt{b^2-4ac}}{2a}$

$a=\dfrac{-(-1)\pm\sqrt{(-1)^2-(4\times 6\times -5}}{6\times 2}$

$a=\dfrac{1\pm\sqrt{121}}{12}$

$a=\dfrac{1\pm11}{12}$

First, take the positive and then take the negative sign to calculate two values of a.

$a=\dfrac{11+1}{12}=1$

$a=\dfrac{1-11}{12}=\dfrac{-10}{12}=\dfrac{-5}{6}$

Therefore the solution of the given quadratic equation 6a² − a − 5 = 0 will be a ( 1 , -5 / 6 ).

To know more about quadratic equations follow

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